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In-s [12.5K]
3 years ago
15

How do I solve this question?

Mathematics
1 answer:
julsineya [31]3 years ago
7 0
As its a rhombus, all sides are of equal length, so 2x +y +1 = x -y  =>   x +1 = -2y            (3x -y -2)/2 = x -y   =>   3x -y -2 = 2x -2y   =>   -y = x -2      
Both equations simultaneously equated =>   2x -4 = x +1   =>   x=5
Plug back in for y   =>   -y = 5 -2 = 3   =>   y = -3
and then the perimeter is 2x +y +1 +x -y + (3x -y -2) = 6x -y -1
6*5 - (-3) -1 = 32 
Perimeter is 32
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Write the Standard Form equation of a line with slope 8/7 and has a y− intercept of 5 .
Leni [432]

Answer:

y=8/7x+5

Step-by-step explanation:

y=mx+b but m is your slope and b is your y intercept.

6 0
3 years ago
A political candidate has asked you to conduct a poll to determine what percentage of people support him. If the candidate only
Nadusha1986 [10]

Answer:

The sample size required is, <em>n</em> = 502.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p\cdot (1-\hat p)}{n}}

The margin of error is:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

Assume that 50% of the people would support this political candidate.

The margin of error is, MOE = 0.05.

The critical value of <em>z</em> for 97.5% confidence level is:

<em>z</em> = 2.24

Compute the sample size as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}

           =[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502

Thus, the sample size required is, <em>n</em> = 502.

4 0
3 years ago
Brian ate 2/3 of a pizza. His friend, Joseph, ate 1/4 of what was left. How much pizza did Joseph eat?
Natasha_Volkova [10]

Answer:

1/12

Steps:

1 - 2/3 = 1/3

1/3 / 4 = 1/3 × 1/4 = 1/12

3 0
3 years ago
Can you help me with my work
andrezito [222]

Answer:

1. x = ±9

2. x=\pm \sqrt{13}

3. 12 and -12.

4. Antoine is incorrect. There exists two solutions x=5 and x= -5.

Step-by-step explanation:

According to the questions,

Problem 1. x^{2}-81=0 i.e. x^{2}=81 i.e. x = ±9.

Problem 2. 2x^{2}-26=0 i.e. x^{2}-13=0 i.e. x^{2}=13 i.e. x=\pm \sqrt{13}

Problem 3. [tex]f(x)=x^{2}-144[tex]

To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.

Thus, the options are 12 and -12.

Problem 4. We have [tex]f(x)=x^{2}+25[tex]

For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.

Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.

8 0
3 years ago
Dory and nemo go to Taco Bell for lunch.dory orders three soft tacos and three double deckers for $11.25 nemo pays $10.00 for fo
Maslowich
If we let x be the price for soft tacos and y be that of double deckers, then from the question, we'll have 3x + 3y = 11.25 x + y = 11.25/3 x + y = 3.75 (1) in addtion, we also have 4x + 2y = 10.00 2x + y = 5.00 y = 5.00 - 2x (2) <span>Substituting y from equation (2) into equation (1), x + (5.00 - 2x) = 3.75 -x = 3.75 - 5.00 x = 1.25 y = 5.00 - 2(1.25) = 2.50 </span>
5 0
3 years ago
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