H=(√3)*a/2 = 41.2
So, a=2*41.2/√3=47.6
Answer:
A=640.88
Step-by-step explanation:
if the diameter is 12, the radius , r=12/2=6
we have r=6, h=11
Surface area, A= 2πrh+2π r^2
A=2*3.14*6*11+2*3.14*(6)^2=640.88
The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .
In the question ,
it is given that ,
the the exponential function is y = 660(0.902)ˣ
we need to determine that , the equation represents a growth or decay .
0.902 is the variable that will determine a growth or decay .
Since, 0.902 is less than 1 , so it represents a decay function .
To find the rate we subtract 0.902 from 1
= 1 - 0.902
= 0.098
= 9.8% decrease rate
Therefore , The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .
The given question is incomplete , the complete question is
Identify if it's Growth or Decay , and determine the percentage rate of increase or decrease , the function is y = 660(0.902)ˣ ?
Learn more about Growth and Decay here
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Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.
<h3>Given information-</h3>
The triangle for the given problem is shown in the image below.
Form the figure the length of the each side is 
units.
As all the sides are equal thus the 
is a equilateral triangle in which the height of the divides the triangle into two equal part of the length 
at point <em>R.</em>
<h3>Height of the triangle-</h3>
Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.
Now in the 
, the length of the hypotenuse is units and the length of the base is units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,
Solve for <em>h,</em>
<em />
<em />
<em />
<em />
Thus the height of the tringle is 24 units. Hence option 2 is the correct option.
Learn more about the equilateral triangle here;
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Your answer for this one is A....use the distributive property
