3 years ago

BRAINLIEST AND 50 PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!HURRY!!!!!!!!!!!!!

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

Answer:

Step-by-step explanation

$(8 * 10) + ( 2 * \frac{1}{100} ) + ( 9 * \frac{1}{1000} )$

⇒ 80 + ( 2 * 0.01 ) + ( 9 * 0.001 )

⇒ 80 + 0.02 + 0.009

= 80.029

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When the polynomial is written in standard form, what are the values of the leading coefficient and the constant? 5x + 2 - 3x^2

ANTONII [103]

5x+2-3x^2
-3x^2+5x+2
coefficient is -3
constant is 2

6 0

3 years ago

Indicate the equation of the given line in standard form, writing the answer below.

scZoUnD [109]

Answer: $y-\frac{11}{2}=6(x-2)$

Step-by-step explanation:

For it to bisect the segment, we need to find the midpoint.

The midpoint is $\left(\frac{-1+5}{2}, \frac{6+5}{2} \right)=\left(2, \frac{11}{2} \right)$ .

Now, for it to be perpendicular, we need to use the fact that perpendicular lines have slopes that are negative reciprocals of each other.

The slope of the given segment is $\frac{6-5}{-1-5}=-\frac{1}{6}$ , so the slope of the perpendicular bisector is 6.

Thus, the equation of the line in point-slope form is $\boxed{y-\frac{11}{2}=6(x-2)}$

4 0

2 years ago

How do you solve :<br><br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="Tex

Neporo4naja [7]

$x^2=\dfrac{2}{3}\to x=\pm\sqrt{\dfrac{2}{3}}\\\\x=-\dfrac{\sqrt{2}}{\sqrt3}\ \vee\ x=\dfrac{\sqrt2}{\sqrt3}\\\\x=-\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\ \vee\ x=\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\\\\\boxed{x=-\dfrac{\sqrt6}{3}\ \vee\ x=\dfrac{\sqrt6}{3}}$