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Yanka [14]
3 years ago
15

Can you help meh answer for brianliest

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
6 0

Answer:

1 13/30      1 13/20      1/6

Step-by-step explanation:

because i am smart

Yakvenalex [24]3 years ago
4 0

Answer:

1st One- 1 13/30

2nd One- 1 13/20

3rd One- 1/6

Step-by-step explanation:

Because yes

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Fofino [41]

Answer:

You’ll end up at (2, 0)

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3 years ago
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Given: WY=ZX<br><br> A is the midpoint of WY.<br><br> A is the midpoint of ZX.<br><br> Prove: WA =ZA
navik [9.2K]

Answer:

Given information: WY=ZX, A is the midpoint of WY and A is the midpoint of ZX.

To prove :  WA =ZA

Proof:

A is the midpoint of WY, it means A divides WY in two equal parts.

WA=AY

So, WY is twice of WA.

WY=2WA            .... (1)

A is the midpoint of ZX, it means A divides ZX in two equal parts.

ZA=AX

So, ZX is twice of ZA.

ZX=2ZA         ... (2)

WY=ZX                        (Given)

Substitute the values from equation (1) and (2).

2WA=2ZA

Divide both sides by 2.

WA=ZA

Hence proved.

5 0
3 years ago
7
ella [17]

Given:

Two similar rectangles.

To find:

The area of the larger rectangle.

Solution:

Let x be the other side of the larger rectangle.

Corresponding sides of similar figures are always congruent.

\dfrac{x}{1}=\dfrac{4}{2}

x=2

The other side of larger rectangle is 2 cm.

We know that, area of rectangle is

Area=Length\times Width

So, area of the larger rectangle is

Area=4\times 2

Area=8

Therefore, the area of the larger rectangle is 8 sq. cm.

6 0
3 years ago
The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in
Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

*<em> Lets explain how to solve the problem</em>

- Any point will be equidistant from the x-axis and the y-axis must have

 equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

 because the distance from the x-axis to the point is 4 (y-coordinate)

 and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

 (x_{1},y_{1})  and (x_{2},y_{2}), then

 x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

* <em>Lets solve the problem</em>

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ x=\frac{p+p+2q}{2}

∴ x=\frac{2p+2q}{2}

- Take 2 as a common factor from the terms of the numerator

∴ x=\frac{2(p+q)}{2}

- Divide up and down by 2

∴ x = p + q

∵ y=\frac{q+q+2p}{2}

∴ y=\frac{2q+2p}{2}

- Take 2 as a common factor from the terms of the numerator

∴ y=\frac{2(q+p)}{2}

- Divide up and down by 2

∴ y = q + p

∴ <em>The mid point of AB is (p + q , q + p)</em>

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

   x-axis and the y-axis

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Answer:

deze nuts thanks u

Step-by-step explanation:

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