Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
Answer:
15 seats
Step-by-step explanation:
It is given that section A of a theater contains 12 rows of 15 seats each.
Now, it is also given that section B contains only 10 rows it has an equal number of seats the same as section A.
As the number of seats in each row of section A is 15, so, the number of seats in each row of section B will be 15 and the same as section A. (Answer)
X/2+1/3=x/3+1/2
x/2=x/3+1/2-1/3
x/2 - x/3 = 3/6 - 2/6
x/2 - x/3 = 1/6
3x/6 - 2x/6 = 1/6
x/6 = 1/6
x = 1/6 * 6
x = 1
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Answer: 45%
Step-by-step explanation: There's 9 people over the age of 14. And 9 divided by the total number, 20, gives you 0.45. 0.45 multiplied by 100 is 45.
