<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
D). 6 3/4
Step-by-step explanation:
Given,
The three eggs with the heaviest weights are;
ounces
ounces, &
2 ounces
To find,
The total weight of the three heaviest eggs =
ounces +
ounces + 2 ounces
= 5/2 + 9/4 + 2/1
Taking the L.C.M. of 2, 4, and 1,
= 10/4 + 9/4 + 8/4
= (10 + 9 + 8)/4
= 27/4 or 6 3/4
Anything over 12/6 will be greater than 4/2 such as 19/6 or 28/6
Answer:
v = 2419200in³
Step-by-step explanation:
v=l*b*h
=240*84*120
=2419200in³
You could multiply 118.56 by .16 which is 19 dollars rounded and subtract 19 from 117.56 to get your answer