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diamong [38]
3 years ago
5

Please need it in 5 mins

Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

70,110,110,110

Step-by-step explanation:

I'm Asian and I was less than 5 minutes

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A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn
tester [92]

Answer:

a) We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

b) z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

c) p_v =2*P(z  

d) Null hypothesis:p=0.35  

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

\hat p=\frac{522}{1562}=0.334 estimated proportion of people who have heard of a new electronic reader

p_o=0.35 is the value to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Part a

We want to test the claim that 35​% of adults have heard of the new electronic reader, then the system of hypothesis are.:  

Null hypothesis:p=0.35  

Alternative hypothesis:p \neq 0.35  

And is a two tailed test

Part b

The statistic for this case is given :

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326  

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

p_v =2*P(z  

Part d

The null hypothesis for this case would be:

Null hypothesis:p=0.35  

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0
3 years ago
500 cats were chosen. 52% of the cats liked to sleep inside the house. Fish was the favorite dish of 25% of those cats, while 62
Alex777 [14]
You would need to take 500 * .52 = 260 next take 260 * .25 to find how many cats like fish which equals 65, the probability that it likes fish and it sleeps inside can be found by taking .52 * .25 = .13 so there would be a 13% chance of picking a cat that sleeps indoors and likes fish, 435 cats dont like fish found by taking 500-65=435 and finally to find how many cats sleep outside take 500-260=240 then take 240 * .625 = 150 then 240-150 = 90 so 90 cats like to sleep outside and like fish thats it!=) Hope this helps!
3 0
3 years ago
Read 2 more answers
In at least one complete sentence, describe in words which numbers are included in this
ikadub [295]

The numbers included in this interval are from -12/17 and on.

5 0
2 years ago
4/5x - 1/4x = 11, find x
aivan3 [116]

Answer:

x= 20

Step-by-step explanation:

1. multiply both sides by 20: 16x-5x= 220

2. Combine like terms: 11x=220

3. Divide: x=20

6 0
3 years ago
A bag has 3 red marbles, 2 blue, 4 greens and 1 yellow. What is the probability of pulling a blue, putting it back
Tomtit [17]

Answer: 2/25

Step-by-step explanation: Since we are replacing the marbles, these two events are independent which means that the outcome of the first does not affect the outcome of the second.

First find the probability of selecting a blue marble.

There are 2 favorable outcomes, the blue marbles,

and 10 possible outcomes, all the marbles in the bag.

So the probability of selecting a blue marble is 2/10 or 1/5.

<em>Always reduce when finding probability</em>

<em></em>

Now we find the probability of selecting a green marble.

There are 4 green marbles and 10 total so the probability of

selecting a green marble is 4/10 or 2/5.

Now we multiply the probabilities.

So we have 1/5 x 2/5 or 2/25.

3 0
3 years ago
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