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3 years ago

Which expression is equivalent to 3 p+15? (4 points)

Mathematics

1 answer:

Deffense [45]3 years ago

7 0

Answer:

um, I am confused on the answer options, but 3(p+5) is equivalent

Step-by-step explanation:

3p+15 is the same a 3(p+5) because in 3(p+5) we have to use the distribution property

So, it is 3p +15 here's a picture to explain it better

(3(p+45) would be too big of a number as you also use the distribution property and it would be 3p+135)

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liq [111]

Answer:

2.53800027 ^9

Step-by-step explanation:

the product of both numbers is this.

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6 0

3 years ago

Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give

Aloiza [94]

Answer:

$y = 4e^2x - 3e^2$

Step-by-step explanation:

$f(x) = e^{2x^2}$

lets calculate the derivate of f using the chain rule:

$f'(x) = e^{2x^2}* (2x^2)' = e^{2x^2}*4x = 4e^{2x^2}x$

we have that f'(1) = 4e^2, hence the equation is

$y = f(1) + f'(1) (x-1) = e^2 + 4e^2(x-1)$

or, equivalently,

$y = 4e^2x - 3e^2$

4 0

3 years ago

What number :<br> Decreased by 0% is 800 ?

kaheart [24]

Answer:

800

Step-by-step explanation:

0℅ decrease of 800=800

7 0

3 years ago

You are the manager of a restaurant that delivers pizza to college dormitory rooms. You have just changed your delivery process

lozanna [386]

Answer:

1.4000 ;

0.0807 ;

1.69 ;

Fail to reject the Null

Step-by-step explanation:

Given :

μ = 21 minutes

x = 22.4 minutes

Sample size, n = 36

Standard deviation, s = 6

H0: μ ≥ 21

H1: μ < 21

Test statistic : (x - μ) ÷ s/sqrt(n)

Test statistic : (22.4 - 21) ÷ 6/sqrt(36)

Test statistic : 1.4 ÷ 1

Test statistic = 1.4000

Pvalue : Using the Test statistic value at α = 0.05 ; One - tail test = 0.0807

The t critical value using a critical value calculator ; DF = (n - 1) = 36 - 1 = 35 ; α = 0.05 = 1.69

Decision region :

Reject H0 if

|Test statistic| > |critical value|

1.4 < 1.69

Hence, we fail to reject H0

There isn't enough evidence they delivery time has been reduced below previous mean

4 0

3 years ago

The weight of oranges growing in an orchard is normally distributed with a mean

katrin2010 [14]

Answer:

The percentage is 95.45%

Step-by-step explanation:

In this question, we are tasked with calculating the percentage of oranges weighing between a particular range.

To do this , we use the z-scores of both numbers in the range.

Mathematically, z-score can be calculated as (x - Mean)/SD

Thus we have P(3 <x < 7) = P( (3-5)/1 < z < (7-5)/1)

= P( -2 < z < 2)

Using standard score table, we have

P(-2<z<2) = 0.9545

The percentage is thus 9545/100 = 95.45

8 0

3 years ago