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KonstantinChe [14]
3 years ago
6

What is needed in order to create a magnetic field

Physics
2 answers:
Karolina [17]3 years ago
5 0

magnet

is that a multiple choice question?

Juliette [100K]3 years ago
5 0
All magnetic fields are created by moving charged particles. Even the magnet on your fridge is magnetic because it contains electrons that are constantly moving around inside.
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Which of the following items has the most inertia while at rest?
Vika [28.1K]
The answer should be (c) because the dog is the one which make a sound of ooooooo
3 0
3 years ago
A woman can see clearly with her right eye only when objects are between 45 cm and 155 cm away. Prescription bifocals should hav
Yuri [45]

Answer:

Explanation:

given,

A woman can see object between 45 cm and 155 cm

glasses is 2 cm from the eye

to able to read a book distance = 25 cm

For the  object distant apart

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{\infty}+\dfrac{1}{-153}

\dfrac{1}{f} = - 6.53 \times 10^{-3}

hence, D = - 0.653  m

For the object at the near point

\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}

\dfrac{1}{f}= \dfrac{1}{23} +\dfrac{1}{-43}

\dfrac{1}{f}= 0.0202 cm

hence, D = 2.02 m

8 0
3 years ago
Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distan
aivan3 [116]

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δx=\frac{(Wavelength)(Distance between slit and screen)}{Width}

Δx=\frac{(590/10^{9})(1.90) }{(2.30)}

Δx=0.000000487 m

Hope this helps!

7 0
2 years ago
Read 2 more answers
The hubbles telescopes orbit is 5.6 x10 ^5 meters above earths suface. the telescope has a mass os 1.1 x10^4 kilograms. earth ex
Andru [333]
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg

Fam
7 0
3 years ago
What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

learn more about pressure:

brainly.com/question/22613963

#SPJ4

5 0
1 year ago
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