1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmasim [6.3K]
3 years ago
9

Divers found two substances on the bottom of the ocean. At room temperature, both substances are liquid. Scientists then transfe

rred the same amount of energy out of both substances. When a scientist checked again, Substance 1 had changed phase, but Substance 2 had not. How are Substances 1 and 2 different?
Physics
2 answers:
Lisa [10]3 years ago
7 0

Answer: Hello there!

You know that both substances are liquid at room temperature.

After the scientists transferred the same amount of energy to both substances (this is equivalent to heating them by the same amount), one of them changed phase and the other not.

when you give energy to a liquid, or heat in this case, the next phase is the gas. The fact that substance 1 changed of phase and substance 2 don't, means that substance one has a smaller vaporization point, which means that requires less energy in order to go from the liquid phase to the gas phase (the substance 1 does the transition at a smaller temperature than the substance 2).

shtirl [24]3 years ago
3 0

They have different melting points

You might be interested in
HELP ASAP PLEASE - Which best describes how the arrangement of the sun, moon, and the earth affect the range of the tides during
koban [17]
B. When the sun and the moon are aligned, their combined gravitational force attracts the water, causing super high tides on one side of the planet, and super low tides on the opposite side.
3 0
3 years ago
Read 2 more answers
You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
Citrus2011 [14]

Answer:

\triangle x=3.2*10^-^5 m

Explanation:

From the question we are told that

Height of circular cylinder is h= 1.8m

Diameter of cylinderD=4cm=>0.04m

Horizontal Force  F=900N

Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\

Generally the formula for shear modulus is mathematically represented by

G=\frac{\tau}{\gamma}

Where

G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain

G=\frac{F/A}{\triangle x/L}

G=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900}{\pi r^2}  *\frac{1.8}{\triangle x}

{\triangle x} =\frac{1620}{\pi r^2* 4.0*10^1^0}

\triangle x=3.2*10^-^5 m

5 0
3 years ago
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
2 years ago
Which form of
Soloha48 [4]
I think it’s C b/c it works for me
3 0
3 years ago
MA and VR have no units. Why?
trapecia [35]

Answer:

There is no unit for MA and VR since the unit for both input and output forces cancels out.

3 0
3 years ago
Other questions:
  • I need help with finding the rest of the missing things..like the current (I), resistance, and voltage (v)
    10·1 answer
  • A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple
    15·1 answer
  • What happens to the speed of the
    8·1 answer
  • A wave has a period of 4 seconds. What is its frequency?
    15·1 answer
  • The motion of a particle along a straight line is described by the equation x=6+4t2 -t 4 , where x is in meter and t is in secon
    7·1 answer
  • I need help with this<br>​
    6·1 answer
  • B) A body of mass 10kg initially at rest is subjected to the force of 40N. What is kinetic energy acquired by the body at the en
    14·1 answer
  • What type of process occurs at constant pressure
    10·2 answers
  • True or false: If the net external force on a system is zero, then the momentum of a system is constant even if objects in the s
    15·1 answer
  • A 4.0-kg object has 72 J of kinetic energy.<br> Determine its speed.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!