Pretty sure it’s 4 idk tho this is a tough one. Hahahaha
3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
.................................................
1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25
(x^2 - 1)(x^6 + x^4 + x^2) =
x^2(x^6 + x^4 + x^2) - 1(x^6 + x^4 + x^2) =
x^8 + x^6 + x^4 - x^6 - x^4 - x^2 =
x^8 - x^2 <==
