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3 years ago

Can someone help me in this please???

Mathematics

2 answers:

MArishka [77]3 years ago

3 0

The first one is 15 mornings

Ivan3 years ago

3 0

The first one is 15 mornings

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a recipe calls for cookies for 3 1/4 cups of. sugar.amy already puts in 3 1/9 cups.how many more cups does she nees t put in

prohojiy [21]

$3 \frac{1}{4}-3 \frac{1}{9} \\ \\ \frac{13}{4} - \frac{28}{9} \\ \\ \frac{117}{36} - \frac{112}{36} \\ \\ \frac{5}{36}$

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3 years ago

What are the values of x and y if you answer is not a whole number write it as a decimal and round if neccasasry

den301095 [7]

a) 3x + 5y = 26

b) 2x + 2y = 12

First, we need to find a way to equate either the x terms or the y terms in each equation. a) 6x + 10y = 52

b) 6x + 6y = 36

Then take equation b) from the equation a) to eliminate the x component.

a) 6x + 10y = 52

- b) 6x + 6y = 36

0x + 4y = 16

y = 4 ?

Then substitute the value of y into either equation to find the value of x.

b) 2x + 2y = 12

2x + (2x4) =12

2x + 8 = 12

2x = 4

x = 2

I hope this new information i read helps you maybe understand it and as an example!

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3 years ago

The value of a jewel in 2015 was $17500. The jewel was purchased in 2008, and its value appreciated 2.5%

ArbitrLikvidat [17]

Answer:

$14722.14

Step-by-step explanation:

We are given that

In 2015

The value of jewel=$17500

Rate of appreciation, r=2.5%

We have to find the initial value of the jewel when it was first bought.

Time, n=7 years

Final value= $Initial\;value (r/100+1)^n$

Using the formula

$17500=Initial\;value(2.5/100+1)^7$

$17500=Initial\;value(1.025)^7$

$Initial\;value=\frac{17500}{(1.025)^7}$

Initial value=$14722.14

Hence, the the initial value of the jewel when it was first bought=$14722.14

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3 years ago

Write the fraction 12/28 in the simplest form

ad-work [718]

Answer: 3/7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX

marin [14]

The distance between two points (x₁,y1),(x₂,y₂) is d
$d= \sqrt{(x2-x1)^2 + (y2-y1)^2}$

For the given problem we have
W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = $\sqrt{(4-1)^2 + (5-8)^2}$ = 3√2
The length of WX = $\sqrt{(7-1)^2 + (8-8)^2}$ = 6
The length of WZ = $\sqrt{(1-1)^2 + (2-8)^2}$ = 6
The length of XY = $\sqrt{(4-7)^2 + (5-8)^2}$ = 3√2
The length of ZY = $\sqrt{(1-4)^2 + (2-5)^2}$ = 3√2

∴ WX = WZ ⇒⇒⇒ proved
XY = ZY ⇒⇒⇒ proved
WY = WY ⇒⇒⇒ reflexive property

∴ ΔWYZ is congruent to ΔWYX by SSS method

5 0

3 years ago