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alexgriva [62]
3 years ago
14

Write two expressions that are equivalent to the expression below. (9- c) +(9 -c)+(9- c) +(9- c)

Mathematics
2 answers:
zvonat [6]3 years ago
5 0

Answer:

4( 9  - c)

and

36 - 4c

Step-by-step explanation:

(9- c) +(9 -c)+(9- c) +(9- c)\\\\= ( 9 - c)( 1 + 1 + 1 +1)\\\\=(9 -c) \times 4

or \\\\= 36  - 4c

GREYUIT [131]3 years ago
4 0

Answer:

{ \tt{4(9 - c)}} \\ and \\ { \tt{36 - 4c}} \\  \\ { \underline{ \blue{ \tt{becker \: jnr}}}}

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4 0
3 years ago
The functions f(x)=√x^2+12x+36 and g(x)=x^3-12 are defined below. Which expression is equal to f(x) · g(x)? A.x^4-6x^3-12x+72 B.
Lostsunrise [7]

Answer:

C: x^4+6x^3-12x-72

Step-by-step explanation:

For the function : f(x)=√x^2+12x+36

It can be factorized to

f(x)=√(x+6)²

=x+6

f(x)*g(x)

=(x+6)(x^3-12)

Expand the brackets

=x^4-12x+6x^3-72

rearrange the numbers

x^4+6x^3-12x-72

3 0
2 years ago
Find the value of a and b when x = 12
oksano4ka [1.4K]

Answer:

a=120

b=240

Step-by-step explanation:

if x=12

a=5×2×2×2(x-5)

5×2=10×2×2=40

40(x-5) 40x-200

200=40×\40x=5

b=2×10×12=240

a=120

b=240

7 0
3 years ago
Which of the following are solutions to 2x2 – 8x - 90? Select all that apply.
Bond [772]

Answer:

x=-5, x=9

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} -8x-90  

equate to zero

2x^{2} -8x-90=0  

so

2=-1\\b=-8\\c=-90

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(2)(-90)}} {2(2)}

x=\frac{8\pm\sqrt{784}} {4}

x=\frac{8\pm28} {4}

x=\frac{8+28} {4}=9

x=\frac{8-28} {4}=-5

therefore

The solutions are x=-5, x=9

6 0
2 years ago
Write an equation to help Sage decide how
Softa [21]

Answer:

i think this is the answer:  

d + (a+b+c)

6 0
2 years ago
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