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Ipatiy [6.2K]
3 years ago
15

Find the derivative.

Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

y prime = \frac{2x}{ln(x)} -\frac{x}{(ln(x))^2}

Step-by-step explanation:

y = x^2 / ln(x)

Rewrite equation

y = x^2 * (ln(x))^-1

Use product and chain rule

y prime = 2x(lnx)^-1 + (x^2)(-1(lnx)^-2*(1/x)

Simplify

y prime = \frac{2x}{ln(x)} -\frac{x}{(ln(x))^2}

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