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Anestetic [448]
3 years ago
11

Help please<3 for all questions with solutions plz

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

a) h = -\frac{7}{4}, b)  h = f\,\circ\,g (-5) = \frac{3}{2}, c) h = g\,\circ\,f (-2) = \frac{3}{8}

Step-by-step explanation:

We proceed to solve each exercise below:

a) f(-2) +3\cdot g(0)

h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)

h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)

h = -4+\frac{9}{4}

h = \frac{-16+9}{4}

h = -\frac{7}{4}

b) h = f\,\circ \,g (-5)

h = f\,\circ\,g (x)  = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }

h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }

h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}

h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}

h = f\,\circ\,g (-5) = \frac{3}{2}

c) h = g\,\circ\,f(-2)

h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4  }

h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }

h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}

h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}

h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}

h = g\,\circ\,f (-2) = \frac{-3}{-8}

h = g\,\circ\,f (-2) = \frac{3}{8}

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