Question

A pitcher holds 3/4 gallons of kool-aid. Martin wants to pour equal amounts of kool- aid into 6 smaller cotainers. How much kool-aid will each smaller cotained hold.

Answer 1

Answer:

$\dfrac{1}{8}\ gallons$

Step-by-step explanation:

Amount of kool - aid that the pitcher can hold = $\frac{3}4$ gallons

There are 6 smaller containers in which this kool - aid is to be adjusted.

Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.

To find:

The amount of kool - aid that each container can hold?

Solution:

Volume of all the smaller containers combined = Volume of the kool - aid available

Let the volume of one smaller container = $V$

$V + V + V + V + V + V = \dfrac{3}{4}\ gallons$

$\Rightarrow 6V = \dfrac{3}{4}\ gallons\\\Rightarrow V = \dfrac{3}{4\times 6 }\ gallons\\\Rightarrow V=\bold{\dfrac{1}{8}\ gallons}$

$\frac{1}{8}\ gallons$ of kool - aid is the amount that each smaller can hold.