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Lisa [10]
3 years ago
13

" class="latex-formula"> - 12 = 5n + 5

I need to show my work, please.
Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

n= -3.5

Step-by-step explanation:

n/7 - 12 = 5n +5

+12            +12

n/7 = 5n+17

*7      *7

n = (5n+17)*7

n = 35n + 119

-35n    -35n

-34n = 119

/-34     /-34

n = -3.5

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A explanation would help very much
Leni [432]

Answer:

x = 14

y = 40

Step-by-step explanation:

3y+8 = 128

3y = 120

y = 40

45/20=2.25 (scale factor)

5x-25 = 2.25(2x-8)

5x-25 = 4.5x - 18

.5x = 7

x=14

4 0
3 years ago
What is closure property ?
kvv77 [185]

Answer:

In mathematics, a set is closed under an operation if performing that operation on members of the set always produces a member of that set. For example, the positive integers are closed under addition, but not under subtraction: 1 − 2 is not a positive integer even though both 1 and 2 are positive integers.

Step-by-step explanation:

I hope this helps you out.

5 0
3 years ago
What is the answer to these question<br> 1:1/3y-1/2=5<br> 2:5n+1/2=1/6
Natasha2012 [34]
\frac {1}{3}y-\frac{1}{2}=5\\2y-3 =30\\2y=33\\y=16.5\\\\\\5n+\frac{1}{2}=\frac {1}{6}\\30n+3=1\\30n=-2\\n=-\frac {2}{30} \\n= -\frac{1}{15}
3 0
3 years ago
Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}
Lady_Fox [76]

Answer:

\mathbf{\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 (e^7 -8)}

Step-by-step explanation:

Given that:

\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end  {bmatrix}\ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  \dfrac{4}{2}[e^y -1]^7_0 \ dy

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 [(e^7 -7)-(e^0 -0)]

\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 [(e^7 -7)-1]

\mathbf{\int \int _R \ 4xy e^{x^2 \ y}  \ dA =  2 (e^7 -8)}

3 0
4 years ago
there is a line that includes two point (-1,0) and has a slope of 19. What is its equation in slope-intercept form?​
shusha [124]

Answer:

Step-by-step explanation:

m = 19 ;   (-1,0)

y - y₁ = m (x - x₁)

y - 0 = 19 (x - [-1] )

     y = 19 ( x + 1 )

    y = 19x + 19

4 0
3 years ago
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