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3 years ago

For this graph, mark the statements that are true.

Mathematics

1 answer:

amid [387]3 years ago

6 0

The domain is the set of all real numbers.
The range is the set of all real numbers.

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Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

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3 years ago

Solve the equation for x. show each step of the solution. name the justifications for each step of the solutions.

UkoKoshka [18]

Answer:

What grade is this?

Step-by-step explanation:

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3 years ago

A parabola has a line of symmetry x = -5. The minimum value of the quadratic function that it represents is -7. Find a possible

Ilya [14]

hello :
the parabola's equation is : f(x) = a(x-h)²+k
the verex is (h,k)
line of symmetry x = h
The minimum or maximum value is : k
a possible equation of this parabola is : f(x) = a(x+5)²-7

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Please help find the anwser to question 1 and 2

grin007 [14]

16ft and 25ft sorry if i’m wrong

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3 years ago

Answer this question.. Anyone who want increase the level but having brainliest. then answer

Elanso [62]

Answer:

You did it correctly what answer you want ??

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