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kvasek [131]
3 years ago
11

Scott likes to run long distances. He can run 20 km in 85 minutes. He wants to know how many minutes (m) it will take him to run

52 km, at the same pace.
How long will it take Scott to run 52km?
Mathematics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

221 minutes

Step-by-step explanation:

52 divided by 20 would be 2.6 then you take the 85 and mulitpy it by 2.6 because 52 is 2.6 times more than 20. so 85 times 2.6 would be 221 minutes.

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10t = b - 4

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This is a system of equations. I’ll be solving through substitution.

In the first equation. solving for b (the easier variable to isolate) gives you:

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Substitute this into the second equation:

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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
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\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
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\\ \quad \\
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\\ \quad \\
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\bf \begin{array}{llll}
% right side info
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\\\\

\end{array}\\

\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
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\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


now, notice the template above... now let's see your function \bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}

so.. what do you think was the shift then?
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