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serious [3.7K]
3 years ago
12

What is 1,000,000 written as a power of ten?

Mathematics
1 answer:
Daniel [21]3 years ago
6 0
1 * 10^6 
comma is moved back 6 times
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Find the slope of the line that passes through the points (–1, 6) and (2, 15)
11111nata11111 [884]

Answer:

m=3

Step-by-step explanation:

\frac{15-6}{2-(-1)} =\frac{9}{3} =3

7 0
3 years ago
Timothy is filling fish bowls with pebbles at his fish store. He wants to have $\frac{1}{6}$ of a pound of pebbles in each fish
Luba_88 [7]

Answer:

14

Step-by-step explanation:

Given that:

Each fish bowl to have pebbles of weight equivalent to = \frac{1}{6}

Total pounds of pebbles that Timothy can use = 2\frac{1}{3}

To find:

The greatest value of Total number of fish bowls that Timothy can fill ?

Solution:

First of all, we need to convert mixed fraction into a fractional number and then we also need to see division of two fractions.

Formula:

1. \ p\dfrac{q}{r} = \dfrac{p\times r+q}{r}\\2. \ \dfrac{\frac{a}{b}}{\frac{c}d}=\dfrac{a\times d}{b\times c}

Now, the given mixed fraction can be converted to fractional number as:

2\dfrac{1}{3} = \dfrac{2\times 3+1}{3} = \dfrac{7}{3}

Now, To find the total number of fish bowls that can be filled, we need to divide the total number of pounds with number of pounds of pebbles in each fish bowl.

So, the answer is:

\dfrac{\frac{7}{3}}{\frac{1}{6}}\\\Rightarrow \dfrac{7\times 6}{3\times 1}\\\Rightarrow \dfrac{42}{3}\\\Rightarrow \bold{14}

<em>14</em> number of fish bowls can be filled.

3 0
3 years ago
Big burgers restaurant just got a shipment of ground beef that was 384 oz they make one pound burgers how many burgers can they
Oxana [17]
Depends how many ounces each burger is made with
7 0
3 years ago
Rewrite using the distributive property then solve using gcf. 5(4+3)
Vitek1552 [10]

Answer:

Step-by-step explanation:

5×4+5×3

20+15

25

5 0
3 years ago
A group of market women sell at least one of yam, plantain and maize.12 of them sell maize,10 sell yam and 14 sell plantain,5 se
mina [271]

Let the three items be M, Y and P.

n{M ∩ Y} only = 4-3 = 1

n{M ∩ P) only = 5-3 = 2

n{ Y ∩ P} only = 2

n{M} only = 12-(1+3+2) = 6

n{Y} only = 10-(1+2+3) = 4

n{P} only = 14-(2+3+2) = 7

n{M∩P∩Y} = 3

Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.

8 0
3 years ago
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