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malfutka [58]
3 years ago
9

The sum of two numbers is 43 . the smaller number is 11 less than the larger number. what are the numbers?

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0
Set x as the smaller number and y as the bigger one.
x+y=43
y-11=x

Solve by substitution:
y-11+y=43
2y-11=43
2y=54
y=27
27-11=16
x=16

The numbers are: 27 and 16
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Answer:

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Step-by-step explanation:

If that is a square, then all sides are the same. Therefore, it's a \sqrt{10} by \sqrt{10} shape. We'll use Pythagorean Theorem to find the diagonal.

a^2+b^2=c^2\\\sqrt{10}^2+ \sqrt{10}^2=x^2\\10+10=x^2\\20=x^2\\\sqrt{20}=x\\\sqrt{4*5}=x\\ 2\sqrt{5}=x

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2 years ago
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Yakvenalex [24]

Answer:

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Step-by-step explanation:

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So the area here is (x+2)(x-5).

They are probably not looking for A=(x+2)(x-5) because it requires too little work.

They probably want A in standard form instead of factored form.

Let's use foil:

First x(x)=x^2

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The area in factored form is A=(x+2)(x-5).

The area in standard form is A=x^2-3x-10.

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Answer:

What is the question?

Step-by-step explanation:

8 0
3 years ago
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