3 years ago

Can anyone help me please

Mathematics

2 answers:

vichka [17]3 years ago

8 0

Answer: Your Answer to the equation is in the picture below.

Step-by-step explanation:

Debora [2.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

(X^a2+b2 /x-ab)a-b *(xb2+c2/x-bc)b-c *(xc2+a2/x-ca)c-a

= (xa2+b2+ab)a-b *(xb2+c2+bc)b-c*(xc2+a2+ca)c-a

= xa3- a2b+ab2-b3+a2b-ab2* xb3-b2c+bc2-c3+b2c-bc2 *Xc3-ac2+a2c-a3+ac2-a2c

=xa3-b3+b3-c3+c3-a3

=x0

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Can anyone help me please​

Can anyone help me please