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telo118 [61]
3 years ago
12

Can anyone help me please​

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer: Your Answer to the equation is in the picture below.

Step-by-step explanation:

Debora [2.8K]3 years ago
6 0

Answer:

1

Step-by-step explanation:

(X^a2+b2 /x-ab)a-b *(xb2+c2/x-bc)b-c *(xc2+a2/x-ca)c-a

= (xa2+b2+ab)a-b *(xb2+c2+bc)b-c*(xc2+a2+ca)c-a

= xa3- a2b+ab2-b3+a2b-ab2* xb3-b2c+bc2-c3+b2c-bc2 *Xc3-ac2+a2c-a3+ac2-a2c

=xa3-b3+b3-c3+c3-a3

=x0

=1

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Find the derivative of g(y)=(y-4)*(2y+y^2)
sasho [114]

Answer:

g'(y)=3y^2-4y-8

Step-by-step explanation:

start by foiling out the given function

g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y

next, use the power rule to find the derivative

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5 0
1 year ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
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