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3 years ago

Can anyone help me please

Mathematics

2 answers:

vichka [17]3 years ago

8 0

Answer: Your Answer to the equation is in the picture below.

Step-by-step explanation:

Debora [2.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

(X^a2+b2 /x-ab)a-b *(xb2+c2/x-bc)b-c *(xc2+a2/x-ca)c-a

= (xa2+b2+ab)a-b *(xb2+c2+bc)b-c*(xc2+a2+ca)c-a

= xa3- a2b+ab2-b3+a2b-ab2* xb3-b2c+bc2-c3+b2c-bc2 *Xc3-ac2+a2c-a3+ac2-a2c

=xa3-b3+b3-c3+c3-a3

=x0

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2 years ago

Find the derivative of g(y)=(y-4)*(2y+y^2)

sasho [114]

Answer:

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Step-by-step explanation:

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5 0

1 year ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago

Can anyone help me please​

Can anyone help me please