1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sunny_sXe [5.5K]
4 years ago
15

The lettwrs a e i o u and y are vowels. if one letter of alphabet is chosen at random what is the probability it is a vowel

Mathematics
2 answers:
SashulF [63]4 years ago
7 0
The probability is 6/26
valina [46]4 years ago
4 0
Ok, so there are 26 letters in the entire alphabet. What you have to do is set up a fraction pretty much.
so that is 6 vowels
and 26 letters...
your equation should be:
6/26
then you should technically reduce.
6/26 ->(÷2)->3/13
and that would be all you can do:)
so your overall answer would be;
3/13 (3 over 13)
You might be interested in
Find the missing values of the variables. The diagram is not to scale.
RideAnS [48]

Answer:

B

Step-by-step explanation:

107 and y form a straight angle and are supplementary, thus

107 + y = 180 ( subtract 107 from both sides )

y = 73

The sum of the interior angles of a quadrilateral = 360°

Sum the given angles and equate to 360

117 + 79 + 73 + x = 360, that is

269 + x = 360 ( subtract 269 from both sides )

x = 91

Thus x = 91, y = 73 → B

3 0
3 years ago
30=11+3x find x need asap
kompoz [17]

Answer:

x = 19/3

Step-by-step explanation:

30 - 11 = 3x

3x = 19

x = 19/3

hope it helps!

4 0
3 years ago
Read 2 more answers
Why is it important to use triangles in tessellations
SpyIntel [72]
Because they are apart of the euclidean plane. <span />
8 0
3 years ago
A tennis player makes a successful first serve 51% of the time. If she serves 9 times, what is the probability that she gets exa
aleksley [76]

Answer:

P(X=3)

And we can use the probability mas function and we got:

P(X=3)=(9C3)(0.51)^3 (1-0.51)^{9-3}=0.1542  

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=9, p=0.51)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And we can use the probability mas function and we got:

P(X=3)=(9C3)(0.51)^3 (1-0.51)^{9-3}=0.1542  

4 0
3 years ago
Read 2 more answers
The map shows the location of four places in a city Jade's house is in the same quadrant as the museum which of the following co
Andre45 [30]
The answer is the first answer -3-4
6 0
3 years ago
Other questions:
  • Please help me ??????
    9·1 answer
  • the strauss insurance company laid off 20% of its employees one year and then increased its staff by 12 1/2% the following year.
    9·1 answer
  • Someone can help me, pleasee​
    15·1 answer
  • Create an original rational function that has at least one asymptote (vertical, horizontal, and/or slant) and possibly a removab
    6·1 answer
  • 2. Draw a right triangle with side lengths of 3, 4, and 5 units.
    6·1 answer
  • Which inequality is equivalent to -x &lt; 8?
    9·2 answers
  • Please give me an example of via communicative property of multiplication
    12·1 answer
  • Which of the following graphs represents y=x-2
    9·1 answer
  • What is the velocity of a train that is traveling 400 kilometers south in 5 hours
    14·1 answer
  • Ill give brainliest for attempt help needed
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!