I'll assume the ODE is
Solve the homogeneous ODE,
The characteristic equation
has roots at 
and 
. Then the characteristic solution is
For nonhomogeneous ODE (1),
consider the ansatz particular solution
Substituting this into (1) gives
For the nonhomogeneous ODE (2),
take the ansatz
Substitute (2) into the ODE to get
Lastly, for the nonhomogeneous ODE (3)
take the ansatz
and solve for 
.
Then the general solution to the ODE is
Unit rate = 20/4 = 5 m/s
hope it helps
Answer:
448.50
Step-by-step explanation:
299/2 = 149.50
then you take 149.50* 3 to get your answer and that = 448.50
Answer:
B. 6
Step-by-step explanation:
The picture of the question in the attached figure
we know that
A translation and a reflection are rigid transformations, that produce congruent figures'
Remember that
Two figures are congruent if their corresponding sides and their corresponding angles are congruent
In this problem
Triangle JKL and Triangle J'K'L' are congruent
so
substitute the given values
solve for x
Answer:
m∠DBC is 43°
Step-by-step explanation:
Let us solve the question
∵ D is in the interior of ∠ABC
→ That means D divides ∠ABC into two angles ABD and DBC
∴ m∠ABD + m∠DBC = m∠ABC
∵ m∠ABD = (3x + 5)°
∵ m∠DBC = (5x - 7)°
∵ m∠ABC = 78°
→ Substitute them in the equation above
∴ 3x + 5 + 5x - 7 = 78
→ Add the like terms in the left side
∵ (3x + 5x) + (5 + -7) = 78
∴ 8x + -2 = 78
∴ 8x - 2 = 78
→ Add 2 to both sides
∴ 8x -2 + 2 = 78 + 2
∴ 8x = 80
→ Divide both sides by 8
∴ x = 10
→ To find m∠DBC, substitute x by 10 in its measure
∵ m∠DBC = 5(10) - 7
∴ m∠DBC = 50 - 7
∴ m∠DBC = 43°
