Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Well there is 24 hours in a day so 24 - 15 = 9. So he spends 9 hours awake.
Answer:
(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)
Here we have the equation:
We can rewrite this as:
Now we can add and subtract cos^2(x)*sin^2(x) to get:
We can complete squares to get:
and we know that:
cos^2(x) + sin^2(x) = 1
then:
This is the closest expression to what you wrote.
We also know that:
sin(x)*cos(x) = (1/2)*sin(2*x)
If we replace that, we get:
Then the simplification is:
Answer:
8 and -2
Step-by-step explanation:
Let the numbers be l and s.
We have equations:
l = 5s + 18
3l + 4s = 16
Solve for s by substituting l into the second equation:
3(5s + 18) + 4s = 16
15s + 54 + 4s = 16
19s = 16 - 54
19s = -38
s = -38/19
s = -2
Find the value of l:
l = 5(-2) + 18
l = -10 + 18
l = 8
x = 7
y = 8
All I did was assume x was 7 and y was 8. I added 4, 6, 7, 8, and 10 together. I got 35. Then, I divided by five (since that's how many numbers are shown) and I got 7 for the mean. 7 is the median, and the 7 is the mean gotten from 4, 6, 7, 8, and 10. Therefore, x must equal 7 and y must equal 8.
