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prohojiy [21]
3 years ago
9

Is (-1,8),(0,15),(1,-4),(2,0) a function

Mathematics
2 answers:
butalik [34]3 years ago
5 0

Answer:

?

Step-by-step explanation:

It could be

Tasya [4]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

Yes because it is a one-to-one relation. Every x-value maps to a unique value of y.

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Yesterday 96 people attended the school band concert, and 3/4 of them stayed for the cookies and punch. How many people stayed f
kupik [55]

72 people stayed, because 96 ÷ 4 = 24, and 24 * 3 is 72.

6 0
3 years ago
Negetive 3 is less than 3x equal to 9
icang [17]
Yes that is true because -3=3 so -3 is less
4 0
3 years ago
Read 2 more answers
Find the MEAN 8, 2, 22,5, 3, 12, 4*
Triss [41]

Answer:

The mean is 8.

Step-by-step explanation:

The mean is the sum of a set of numbers divided by the number of numbers in a set. In this case, you add up all the numbers to get 56, and divide by 7 to get 8.

5 0
3 years ago
Read 2 more answers
Solve for n: c= 6n−5g /11t
qwelly [4]

Answer: \frac{11tc+5g}{66t}=n

Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

3 0
3 years ago
Evaluate <br> (-315) ×4<br> with the correct explaination
Naya [18.7K]

\Large\textsf{\textbf{Answer\::}}

-1, 260

\large\textsf{\textbf{Calculations\;:}}

First , take a look at the signs of the numbers we're asked to multiply .

One of them is negative , and the other one is positive .

If we have a negative number times a positive number , the product is a positive number .

Multiply :

(-315) × 4

-1, 260 (Ans)

\footnotesize\text{hope\:helpful~}

3 0
2 years ago
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