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umka2103 [35]
2 years ago
11

What is the value of Sx3 + 4y3 when x=4 and y=3?

Mathematics
2 answers:
Oliga [24]2 years ago
6 0
Sx3 + 4y3
12S + 12y
12S + 36

That’s the best I can do because there is no value of S. Just times 12 and the value of S, and add that to the 36 as shown. Hope this helps!
rjkz [21]2 years ago
4 0

Step-by-step explanation:

is there any value for S??

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
K=1/2mv squared <br> Rearrange the formula to solve for m
musickatia [10]

Answer:

<h2>m = k  / 1/2 over v</h2>

Step-by-step explanation:

1/2mv = k

rearranged can be:

m = k  / 1/2 over v

5 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Pwese help ill give brainlyest
Luda [366]

Answer:

y=(14-8x) divided by 2

Step-by-step explanation:

minus 8x from both side you get

2y=14-8x

then you divide by 2

y=(14-8x) divided by 2

thats the furthest it can be simplified

4 0
2 years ago
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Papessa [141]

Answer:

432 ft^2

Step-by-step explanation:

4 0
3 years ago
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