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3 years ago

£245 £140 £525 £174 £195 £163 £140 what is the mode?

1 answer:

5 0

The mode is the number that repeats itself the most in a sequence. In this case, the mode will be £140 since it repeats itslef the most (2 times).

Hope it helped,

BioTeacher101

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Kianna started her homework at 4:30 pm. She finished at 5:05 pm. How many SECONDS did it take her to finish her homework? *

lozanna [386]

Answer:

2100 second

Step-by-step explanation:

4:30 pm to minutes

4 × 60 + 30 = 240 + 30

= 270 minutes

5:05 to minutes

5 × 60 + 5 = 300 + 5

= 305

4:30 to 5:05

305 - 270

= 35 minutes

35 minutes to second

35 × 60

= 2100 second

6 0

3 years ago

Read 2 more answers

A small fruit basket contains the fruit shown. A large basket has the same ratio of fruits as the small basket. If the large bas

yarga [219]

Answer: i don’t know

Step-by-step explanation: my brain hurts from trying to figure this out sorry

5 0

3 years ago

Charlie puts $50000 in a stock account, but it loses money at a rate of 20%

Alina [70]

Answer:

You dind't include the answer choices but it should look something like

$50000(.8)^t$

4 0

3 years ago

Value expression of 3^5 / 3^3

suter [353]

Answer:

Step-by-step explanation:

3^5 = 243

3^3 = 27

243 / 27 = 9

Hope this helps :)

3 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago