Around 4 times, maybe 3
Step-by-step explanation:
there's 2 red 3s and there's 52 cards in a deck. so u have a 2/52 chance to get a red 3 so its about a 4/104 chance to get a red 3 if u draw 1 card 100 times
Answer:
![2\frac{7}{10}](https://tex.z-dn.net/?f=2%5Cfrac%7B7%7D%7B10%7D)
Step-by-step explanation:
First, find the LCM and multiply through:
![12(\frac{2x-1}{4} ) +12(\frac{x}{3})=12(2)](https://tex.z-dn.net/?f=12%28%5Cfrac%7B2x-1%7D%7B4%7D%20%29%20%2B12%28%5Cfrac%7Bx%7D%7B3%7D%29%3D12%282%29)
The LCM will cancel out the denominators (note that braket symbolizes Multiplication):
:3(2x-1) +4(x)=24
:6x-3+4x=24
Group like terms:
6x+4x=24+3
10x=27
Divide through by 10 to eliminate the coefficient of x
![\frac{10x}{10}=\frac{27}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B10x%7D%7B10%7D%3D%5Cfrac%7B27%7D%7B10%7D)
: x=![\frac{27}{10}=2\frac{7}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B10%7D%3D2%5Cfrac%7B7%7D%7B10%7D)
For this case, what you must do is to observe in the table the values that take both functions at the moment of being evaluated with different values of x.
We have then that:
for x = 0
f (0) = 1
g (0) = 1
For x = 1
f (1) = 3
g (1) = 3
Therefore, in both cases:
f (x) = g (x)
Thus, the solution values are:
C. x = 0
D. x = 1
answer:
C. x = 0
D. x = 1
There r 4 sides the bottom and the 3 sides