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laila [671]
3 years ago
13

2b=6a-14,3a-b=7 how to work it out

Mathematics
2 answers:
pshichka [43]3 years ago
5 0
So, since there are two equations, we can substitute one of them into the other. In this case, it would be easiest to substitute 2b=6a-14 into the other equations. But first, simplify by dividing both sides by 2. You bet b=3a-1

We can now plug this into the other equation
Sine the equation b=3a-1 results in the value of b, we have to plug in for the value of b in the other equation

So this is what we get after plugging in:
3a-(3a-1)=7
Now, simplify. 3a-3a+1=7
Since 3a-3a = 0, this equation results in a no solution

Answer:
The result is a no-solution, or Ф

Hope this helped!! :D
dmitriy555 [2]3 years ago
5 0
2b=6a-14
3a-b=7
(rearrange so that all the a's b's and numbers line up) *better if number alone
2b - 6a = -14
-b + 3a = 7
(never have a negative number in the front so change whole equation)
2b - 6a = -14
  b - 3a = -7

now try to get ride of some numbers.....get rid of the negative 6 and 3 by finding a way to make the numbers the same

2b - 6a = -14 
2b - 6a = -14 ......multiply each number by two and you get the same equation as above

It is impossible to find a or be because the equations are the same just one in a reduce form







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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe
nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let D^c be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that  one person in 10,000 people has a rare genetic disease.

So,P(D)=\frac{1}{10000}

Only 0.4% of the people who don't have it test positive.

P(A|D^c) = probability that a person is tested positive given he don't have a disease = 0.004

P(D^c)=1-\frac{1}{10000}

Formula:P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}

P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}

P(D|A)=\frac{2470}{2471}=0.9995

P(D|A)=0.9995

A)The probability that someone who tests positive has the disease is 0.9995

(B)

P(D^c|A^c)=probability that someone does not have disease given that he tests negative

P(A^c|D^c)=probability that a person tests negative given that he does not have disease =1-0.004

=0.996

P(A^c|D)=probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}

P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}

P(D^c|A^c)=0.99999

B)The probability that someone who tests negative does not have the disease is 0.99999

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Answer:

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Step-by-step explanation:

<u>Slope-intercept form</u>

y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is -5, m= -5.

Substitute m= -5 into the equation:

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To find the value of c, substitute a pair of coordinates that the line passes through into the equation:

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Answer:

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Answer:X2 = 5

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ΔX = 4

ΔY = 3

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When x=0, y = 0.25

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