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iVinArrow [24]
3 years ago
9

Consider the following navigation scenario. A ship on the open ocean is traveling in the direction shown below. On a coordinate

plane, a vector goes up and to the right in quadrant 1 and forms a 30 degree angle with the y-axis. How would the captain report his navigational vector as a bearing? N60˚E E60˚N N30˚E E30˚N
Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer: C. N30degrees E

Step-by-step explanation:

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What is the solution to the system of 4x-3y=1 and y+2x=3?
Svetradugi [14.3K]
By any chance will it be (1,1)
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3 years ago
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20 years ago, father's age was 5 times his son's age. Now his age is 10 years more than twice his son's present age. Find their
Montano1993 [528]

Step-by-step explanation:

x = father's age now

y = son's age now

x = 2y + 10

x - 20 = 5(y - 20) = 5y - 100

using the first in the second equation :

2y + 10 - 20 = 5y - 100

-10 = 3y - 100

90 = 3y

y = 30

x = 2y + 10 = 2×30 + 10 = 60 + 10 = 70

the father is now 70 years old, the son now 30 years old.

6 0
2 years ago
What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
3 years ago
The probability it will rain tomorrow is 1/2. The probability that our team will win tomorrow's basketball game is 3/5. Which ex
irga5000 [103]

Answer:

4.

Step-by-step explanation:

if the probability it win is 3/5 then 5/5 - 3/5 equals 2/5

which you multiply with 1/2

hope this helps

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2 years ago
On both of the lines
Mamont248 [21]
Yes on day 7, they both have 46 dollars
3 0
3 years ago
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