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3 years ago

Find the equation of the circle centre (3-2)radius 2 unit

Mathematics

1 answer:

il63 [147K]3 years ago

3 0

Answer:

(x - 3)^2 + (x + 2)^2 = 4

Step-by-step explanation:

Equation of circle:

(x - h)^2 + (x - k)^2 = r^2

(h, k) = (3, -2)

r = 2

(x - 3)^2 + (x - (-2))^2 = 2^2

(x - 3)^2 + (x + 2)^2 = 4

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Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =

Genrish500 [490]

So here is how we are going to find out what is ED.
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, (AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
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Therefore, the measurement of ED is 5.
Hope this answer helps. Let me know if you need more help next time!

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Find the equation of the circle centre (3-2)radius 2 unit​

Find the equation of the circle centre (3-2)radius 2 unit