(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
man just try to get the answer right yourself
27= 3x3x3
54 = 3x3x3x2
so 27/54 = 3x3x3 /<span>3x3x3x2 by simplifying = 1/2</span>
Answer:
378+567-142÷5= 916.6
456(325-541)÷32= -3078
Step-by-step explanation:
