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STALIN [3.7K]
3 years ago
13

The register in the CPU is not the same as the RAM.

Computers and Technology
1 answer:
omeli [17]3 years ago
5 0
The answer is true ..........
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Which operator is used for quotient division in java​
Darya [45]

Answer:

Explanation:

In the above expression 7 is divided by 2, so the quotient is 3 and the remainder is 1. Approach: Divide the dividend by the divisor using / operator. Both dividend and divisor can be of any type except string, the result will also be computed accordingly. Get the remainder using % operator.

5 0
3 years ago
If you attempt an edgeunity quiz is your latest attempt the one counted?
tekilochka [14]

Answer:

Hello

Explanation:

Hello profile picture of a nub how are you doing today?

8 0
3 years ago
I need help for preparing for a presentation. Can someone give me advice so I don't have a panic attack again?​
irina1246 [14]

Answer:

Slide selection

Title slide

Content wise slides

Little short animations

Conclusion slide

Thank you slide

Dont forget to use Times New Roman font as using this font makes people easier to understand the concept.

Give attractive headings

Give 2 minutes per each slide for explanation

Make this presentation very good with confidence and don't forget to include tactful facts

Dont get a panic attack Haha

4 0
3 years ago
Read 2 more answers
What is the Matlab command to create a vector of the even whole numbers between 29 and 73?
Nana76 [90]

Answer:

x = 29:73;

x_even = x(2:2:end);

Explanation:

In order to create a vector in Matlab you can use colon notation:

x = j:k

where <em>j</em> is 29 and <em>k</em> is 73 in your case:

x = 29:73

Then you can extract the even numbers by extracting the numbers with even index (2,4,6,etc.) of your vector:

x_even = x(2:2:end);

In the line of code above, we define <em>x_even</em> as all the elements of x with even index from index 2 till the end index of your vector, and an increment of 2 in the index: 2,4,6,etc.

If you want the odd numbers, just use the odd indices of your vector:

x_odd = x(1:2:end);

where <em>x_odd</em> contains all the elements of <em>x</em> with odd index from index 1 till the end index, and an increment of 2: 1,3,5,etc.

6 0
3 years ago
Write a program that asks for the names of three runners and the time, in minutes (no seconds, etc.), it took each of them to fi
Crank

Answer:

Complete python code with explanation and output results is given below

Explanation:

User is asked to input names of runners and their finishing time

We have to determine first, second and third according to their finishing time.

if else conditioning is used to determine who has lowest finishing time.

Outer if is used to decide first position and inner if is used to decide second and third position.

str() function is used to concatenate the integer variable with string

Code:

runner1 = input("Please enter name of the runner1 ")

time1 = int(input("Please enter the time of runner1 "))

runner2 = input("Please enter name of the runner2 ")

time2 =int(input("Please Enter name of the runner2 "))

runner3 = input("Please enter name of the runner3 ")

time3 =int(input("Please Enter name of the runner3 "))

if(time1 < time2 and time1 < time3):  

   if(time2 < time3): // to decide 2nd and 3rd position

       print(runner1+" has finished First with time: "+str(time1))

       print(runner2+" has finished Second with time: "+str(time2))

       print(runner3+" has finished Third with time: "+str(time3))

   else:

       print(runner1+" has finished First with time: "+str(time1))

       print(runner3+" has finished Second with time: "+str(time3))

       print(runner2+" has finished Third with time: "+str(time2))

if(time2 < time1 and time2 < time3):  

   if(time1 < time3):

       print(runner2+" has finished First with time: "+str(time2))

       print(runner1+" has finished Second with time: "+str(time1))

       print(runner3+" has finished Third with time: "+str(time3))

   else:

       print(runner2+" has finished First with time: "+str(time2))

       print(runner3+" has finished Second with time: "+str(time3))

       print(runner1+" has finished Third with time: "+str(time1))

if(time3 < time1 and time3 < time2):

   if(time2 < time1):    

       print(runner3+" has finished First with time: "+str(time3))

       print(runner2+" has finished Second with time: "+str(time2))

       print(runner1+" has finished Third with time: "+str(time1))

   else:

       print(runner3+" has finished First with time: "+str(time3))

       print(runner1+" has finished Second with time: "+str(time1))

       print(runner2+" has finished Third with time: "+str(time2))

Output:

Program has been tested with multiple inputs and results are accurate as per problem specifications.

Please enter name of the runner1 danny

Please enter the time of runner1  45

Please enter name of the runner2  sam

Please enter the time of runner2  34

Please Enter name of the runner3  tedd

Please enter the time of runner3  23

tedd has finished First with time: 23

sam has finished Second with time: 34

danny has finished Third with time: 45

5 0
4 years ago
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