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Neko [114]
3 years ago
14

PLEASE HELP! 10 Points!!

Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0
90 degrees bc its a right angle
vichka [17]3 years ago
4 0
90 degrees or a right angle
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Rectangle FGHJ is transformed according to the rule T(–3, –2)ry = x. What is the y-coordinate of J”?
irga5000 [103]
We have that
 the point J (10,-6)
the rule is-----------(x,y)-------------------> (x-3, y-2)
therefore
J (10,-6)----------------- > (10-3,-6-2)--------> (7,-8)

the answer is 
<span>the y-coordinate of J” is -8</span>
8 0
3 years ago
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If a soup recipe calls for 1 cup of carrots for every 3 cups of chicken, how many cups of carrots are needed if we have 18 cups
AveGali [126]
How many 3's are there in 18? 6! So we need 6 cups of carrots for 18 cups of chicken!
6 0
2 years ago
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Select the correct answer.
Luba_88 [7]
I think it Is B.....
7 0
2 years ago
Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x 2) f(x) = (x – 2)(x 2) f(x) = (x 1)(x – 2)
makvit [3.9K]

The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

<h3>How to determine the function?</h3>

For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:

(h,k) = (0,y)

A quadratic function is represented as:

f(x) = (x - h)^2 + k

So, we have:

f(x) = (x - 0)^2 + k

Evaluate

f(x) = x^2 + k

From the list of options, we have:

f(x) = (x - 2)(x + 2)

Expand

f(x) = x^2 - 4

Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

Read more about vertex at:

brainly.com/question/18797214

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8 0
2 years ago
Convert the polar coordinates (-3, -60°) to Cartesian coordinates.
notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x

#Using the illustration above, we can express our polar coordinates as:

-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}

#Solve simultaneously to solve for x and y:

(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\  y \ in\  i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0
2 years ago
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