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3 years ago

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During the "free banking" era, A. only the U.S. Treasury could issue currency. B. value and denominations were standard across t

he nation. C. the number of state chartered banks stayed the same. D. all banks were able to issue currency.

1 answer:

Jlenok [28]3 years ago

6 0

The answer is A. only the U.S. treasury could issue currency

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Solve for x <br> 2/5x=6/5<br> A 12/15<br> B 12/5<br> C 3<br> D 6

Tamiku [17]

C

2/5x=6/5
x=6/5*5/2
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Express your answer in simplest a+ bi form. (8+5i)(3+2i)-(4+i)(4-i)

Elanso [62]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve ~

$\qquad \sf \dashrightarrow \:(8 + 5i)(3 + 2i) - (4 + i)(4 - i)$

$\qquad \sf \dashrightarrow \:[( 8 \sdot3) + (8 \sdot2i) + (5i \sdot3) + (5i \sdot2i)] -[( 4 \sdot4) + (4 \sdot - i) + (i \sdot4) + (i \sdot - i)]$

$\qquad \sf \dashrightarrow \:[24+ 16i + 15i+ 10i {}^{2} ] -[16 - 4 i+ 4i - i {}^{2} ]$

$\qquad \sf \dashrightarrow \:[24+ 31i+ 10 {}{( - 1)} ] -[16 - ( - 1){}^{} ]$

$\qquad \sf \dashrightarrow \:[24+ 31i - 10 {}{} ] -[16 + 1{}^{} ]$

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Dafna11 [192]

That rounds to 645, 000 -644,999

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Maurinko [17]

"Around the garden"= circumference

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19= (3.14)d
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Area= πr^2
A= π(3.0239)^2
A= (3.14)(3.0239)^2
A= 28.71 square feet

ANSWER: 28.71 square feet is the area of the new garden

Hope this helps! :)

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Alla [95]

Hello,

Please, see the attached file.

Thanks.

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