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3 years ago

15

HELP ME PLEASEEEEEE ASAP I REPEAT HELPPP

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

b

Step-by-step explanation:

denominator(5) stays the same

multiply 2 by 4 since that is 1 fourth of an hour.

So now its 8/5

5 goes into 8 1 time with 3 leftover

So the 1 is a whole number now

the leftover fraction 3/5

=1 3/5

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

What is 6c+b÷6,when c=8

worty [1.4K]

6(8)+b/6
48+b/6
b/6=-48
b=-48/6
b=-288

5 0

4 years ago

Christopher Christopher just found beautiful yarn for 20% off at his favorite yarn store. He can make one scarf from 2/3 of a ba

dimaraw [331]

2/3=.6 repeating
12/.6 repeating = 18
13 balls of yarn would be used to make 18 scarves.

7 0

4 years ago

Read 2 more answers

Someone help me plz i really need help if you help me I will help you

taurus [48]

2. 4/6 , 6/9
3. 2/4 , 3/6
4. 8/10 , 12/15

5. =
6. >
7. >
8. =
9. =
10. <
11. =
12.

6 0

4 years ago

Can someone help me asap!!!

amm1812

Answer:

<em>Negative</em>

Step-by-step explanation:

5 0

2 years ago