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Neporo4naja [7]

2 years ago

12

Find the distance of a line given the following points. R(3, 1), W(-1, -2)

1 answer:

olga_2 [115]2 years ago

7 0

Answer:

5 units

Step-by-step explanation:

±√(- 2 - 1)^2 + (- 1 - 3)^2 = ±5 (rej - 5 since distance > 0)

Apply distance formula

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Kamila [148]

Great question goodluck in the future

6 0

3 years ago

Can somebody answer questions i) and j) please

frutty [35]

i)

Pythagorean's theorem: √50

j)

Pythagorean's theorem: √1/2

8 0

3 years ago

12a +5 identify the coefficient

ioda

Answer:

The coefficient is "12"

Step-by-step explanation:

Step 1: Encircle the variable along with its power whose coefficient we are finding.

Step 2: Leave that variable and consider all other numbers or variables written with it. That will be the coefficient.

4 0

2 years ago

Read 2 more answers

HElpPpPp mEeEe pLeAsE

Ivahew [28]

Answer:

<em>b</em><em> </em><em>=</em><em> </em><em>44</em><em> </em><em>feet</em><em> </em>

Step-by-step explanation:

BY Pythagorus theorem :-

=》

$55 {}^{2} = 33 {}^{2} + b {}^{2}$

=》

$3025 = b {}^{2} + 1089$

=》

$b {}^{2} = 3025 - 1089$

=》

$b {}^{2} = 1936$

=》

$b = \sqrt{1936}$

=》

$b = 44$

7 0

2 years ago

What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0

2 years ago