Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
2.8 m = .0028 km
3.5/.0028 = 1259 revolutions
You know two lines y=ax+b and y=mx+n that are perpendicular, so we have the product a*m=-1
+ This line is perpendicular to y=13x-5, so it has equation: y=-1/13x+b
+ And it passes through the point (3;1), so we have x=3, y=1. So 1=-1/13 *3+b
and b= 1+3/13= 16/13
And we have y=-1/13x+16/13
Have fun
Hey there! I'm happy to help!
When you divide fractions, you are technically multiplying by the reciprocal, which is the numerator and denominator flipped. This means that 22/33 divided by 6/9 is equal to 22/33 multiplied by 9/6.
If we multiply these together, we get an answer of 1.
I hope that this helps! Have a wonderful day!
You use the formula a² +b² =c²
so 4² +b² =8²
solve for b
