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OLEGan [10]
2 years ago
14

Aft 10 ft 3 ft 2 ft 6 ft Surface Area = Surfa I need the surface area

Mathematics
1 answer:
ivolga24 [154]2 years ago
3 0

Answer:

Step-by-step explanation:

Front and back

Givens

base = 6 feet

height = 2

Formula

Area = 1/2 B * h

Area = 1/2 * 6 * 2

Area = (2) 1/2 * 12

Area = 12 square feet for both front and back

Base

The base is a rectangle. A rectangle has the formula of  Area =  L*w

Givens

L = 10 feet

W = 6 feet

Area = 10 * 6 = 60

Left roof

The left roof is also a rectangle. Area = L*w

Givens

L = 10 feet

W = 3 feet

Area = 3 * 10 = 30 feet^2

Right Roof

The right roof is a rectangle. Area = L*w

Givens

L = 10 feet

w = 4 feet

Area = 4 * 10 = 40 ft^2

Total area

Total Area = right roof + left roof + Base + front and back

Total Area = 40 + 30 + 60 + 12

Total Area = 142 feet ^2

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Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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