The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer: x= -1
y= -2
Step-by-step explanation:
-4x+3y= -2
y=x-1
-------------------
-4x+3(x-1)= -2
-4x+3x-3= -2
-x=1
x= -1
y=-1-1
y=-2
Answer:
The number of tickets for sale at $26 should be 3300
The number of tickets for sale at $40 should be 1700
Step-by-step explanation:
Use 2 equations to represent the modifiers within the problem:
Now you want to find the point at which the variables are changed to make both equations correct, this can be done by graphing and finding the intersection of both lines.
