Answer:
who the holy christmas is ily
Step-by-step explanation:
maybe you call your dog that
wait do you have a dog?
anyways
thanks for the points
Answer:
is the equation of line in slope intercept form.
Step-by-step explanation:
Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.
First ordered pair: (-3,0)
Second ordered pair: (0,4)
We have two points and need to find equation of line in slope intercept form


y-intercept, when x=0 , (0,4)
Equation of line in slope intercept form:
y=mx+b
where,
and b=4
Required equation:

Thus,
is the equation of line in slope intercept form.
Answer:
The statement is missing. The statement is -- "A ray can be part of a line."
The answer is : The converse is not true, so Jahmiah is correct.
Step-by-step explanation:
A conditional statement is represented by showing p → q. It means if p is correct or true, then q is also correct or true.
And the converse of p → q can be shown as q → p.
But we know that the converse of a statement is not always true, it may be true and may not be true.
In the context, the statement is " a ray can be a part of a line." And so the converse would be "A line can be a part of the ray".
So by definition we know that a line is continuous line having no end points, it extends in one direction. While a ray starts from a point and extends to infinity in one direction.
Thus ray is part of line but line is not a part of the ray. So the converse of the statement is not correct.
Hence, Jahmiah is correct.
Answer:
44 swimmers
Step-by-step explanation:


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






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And we're done.....♥️♥️♥️♥️♥️