Hello There!
Write out your equation:

Substitute the values in:

Simplify:


Solve:
It is 6.25.
Therefore, your answer is
6 1/4.
Hope This Helps You!Good Luck :)
- Hannah ❤
It is B just use a calculator hope it helped
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
Answer:
5
Step-by-step explanation:
No. of Zeroes or Roots is equal to the degree of polynomial. Here, the degree of polynomial of the equation is 5. Hence, 5 Zeroes are possible.
-2m-9 is the simplified expression