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3 years ago

What is the ratio of consonants to vowels in the english language?

2 answers:

6 0

There are 26 letters in the English Alphabet. 20 of them are Consonants and 5 of them are vowels. The letter Y is an exception that can fit into either category.

Sergio039 [100]3 years ago

5 0

Answer: 21:5

Step-by-step explanation:

There are 21 consonants and 5 vowels

So 21:5

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15 points help asap 2 math questions

krek1111 [17]

Answer

the first one A the second one B

Step-by-step explanation:

4 0

4 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

Solve for 2:<br> 14 = 2 - (-12)

nasty-shy [4]

Answer:

Step-by-step explanation:

14=z-(-12)

14=z+12

Z=2

8 0

3 years ago

Read 2 more answers

How do i find ratios in word problems?

Anton [14]

Solve or figure out how many to the opposing, simplify if necessary.

8 0

4 years ago

3 (X+2)+8.

zaharov [31]

Answer:

x = -14/3

Step-by-step explanation:

3(x + 2) + 8

= 3x + 6 + 8

= 3x + 14

3x = -14

x = -14/3

4 0

3 years ago