Answer:
False for both
Step-by-step explanation:
Neither of these images are symmetrical vertically nor horizontally.
Answer:
a)= 2
b) 6.324
c) P= 0.1217
Step-by-step explanation:
a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)
b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by
σ_X`1- X`2 = √σ²/n1 +σ²/n2
Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2
so
σ_X`1- X`2 =√20 +20 = 6.324
if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.
Where as Z is normally distributed with mean zero and unit variance.
If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then
Z= 0-2/ 6.342= -0.31625
P(-0.31625<z<0)= 0.1217
The probability would be 0.1217
130
7284/56 = 130 (Rounded)
Answer:
(a-b, c)
Step-by-step explanation:
The midpoints of the two diagonals are the same, so we have ...
(P + (-a, 0))/2 = (O +(-b, c))/2
Multiplying by 2 and subtracting (-a, 0), we get ...
P = (0, 0) +(-b, c) -(-a, 0)
P = (a-b, c)
Answer:
dont worry about it brother here
Step-by-step explanation:
