5x(4x^3 + 3x - 2)
There’s a 5 and a x common.
Answer: There were 10 students in the class on the first day.
Step-by-step explanation:
Let x be the number of students of the first day.
Given: A college writing seminar increased its size by 50 percent from the first to the second day.
i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)
= x +50% of x
= x+0.50x
= (1.50)x
=1.50x
Since, it is given that the total number of students in the seminar on the second day was 15.
i.e. 

Hence, there were 10 students in the class on the first day.
Answer:
wheres the graph
Step-by-step explanation:
it's not theree
Answer:
The test statistic is t = 3.36.
Step-by-step explanation:
You're testing the claim that the mean difference is greater than 0.7.
At the null hypothesis, we test if it is 0.7 or less, that is:

At the alternate hypothesis, we test if it is greater than 0.7, that is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
0.7 is tested at the null hypothesis:
This means that 
Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.
This means that 
Calculate the test statistic



The test statistic is t = 3.36.
Answer:
Pecan cheesecake = $11
Strawberry cheesecake= $19
Step-by-step explanation:
To solve this, we will need to set up a system of equations:
Let's call "Pecan cheesecakes" 'x', and
"Strawberry cheesecakes" 'y'.
We can set up the equations once we have our variables:
276= 13x + 7y
295 = 13x +8y
We will need to subtract these equations from each other to get rid of the 'x' variable. This gives us:
295 = 13x+ 8y
-
276 = 13x+ 7y
19 = y
Therefore, Strawberry cheesecakes cost $19. Plug this into an equation to get the value of 'x':
276= 13x + 7(19)
276 = 13x + 133
143 = 13x
x= $11.
Therefore, Pecan cheesecakes cost $11.