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Delicious77 [7]
3 years ago
7

(4,7)(-12,3) into standard form

Mathematics
1 answer:
solong [7]3 years ago
8 0
You seem to be sharing two points:  <span>(4,7)(-12,3).
But you don't explain what you're looking for.

I must assume you want to find the equation of the str. line thru these 2 pts, in std. form.    Ax+By+C=0.

1.  Find the slope of the line thrugh </span><span>(4,7)(-12,3):  rise is -4 and run is -16.
   Thus the slope is -4/16, or -1/4.
2.  Write out the slope-intercept equation of this line:  subst. m = -1/4 and the coordinates of either given point:

   y = mx + b         becomes  y = (-1/4)x + b

Let's subst. 4 for x and 7 for y:     7 = (-1/4)(4) + b, or
                                                    7 = -1 + b.  Then b = 8.

Convert this to the equation in std. form:

y = (-1/4)x + 8     Mult all three terms by 4 to eliminate fractions.

4y = -x + 32, or 0 = -4y -x + 32, or 4y + x - 32 = 0   (answer)</span>
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Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}

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\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54

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2. Let us find the distance between Cameron and Jamie.

\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{625+2500}

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Therefore, Jamie is about 56 meters away from​ Cameron.

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