$\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}$

4 0

3 years ago

Find the probability when a couple has 6 children at at least one of them is a boy

nexus9112 [7]

Try this solution:
1. Probability (P): 1-[probability_all_the_girls]
2. P=1- 1/2⁶=1- 1/64=63/64≈0.984375.

Note: P_all_the_g=[needed_cases]/[all_possible_cases], where needed cases=1 (all the girls means 'gggggg'), and all possible cases=2⁶=64 (all possible cases means 'gggggg';'bbbbbb';gbbbbb';'ggbbbb';'gggbbb';'ggggbb';gggggb';'bggggg', etc. Total 64 combinations.)

4 0

2 years ago