25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Step-by-step explanation:
the line passes through (0,-2) and perpendicular to the graph of y=5x+7.
solution :
the slope = -1/5
the equation :
y+2 = -1/5 (x-0)
y = -1/5x - 2
The answer is the first one:
bc its not growing by a (-)1/2 and the 3rd one just doesnt make sense
Answer:
10x - 5
Step-by-step explanation:
Perimeter is found by adding up all the side lengths.
(2x-4) + (5x+6) + (3x-7) = 10x - 5
