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OlgaM077 [116]
3 years ago
7

A fair die is a cube with number 1 through 6 on the sides, represented as painted spots. If a fair die is rolled, what is the pr

obability of number 6 landing face up?
Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0

Answer:

1/6

Step-by-step explanation:

There is 1 way for a 6 to land face up out of 6 different possible things to happen, so the probability of 6 landing face up is 1/6

vladimir2022 [97]3 years ago
3 0

Answer:

The First Part is A. 1/6

The Second Part is 1

The Third Part is B. 3

And The Fourth Part is B. Different

Step-by-step explanation:

Just took it. Edg 2021. Hope this helps :) (Da smiley is George, George says hi)

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<span> Do you mean this one? </span>∑

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4 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
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16 is the answer to this question.
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xxTIMURxx [149]

Answer:

=15 1/24

Step-by-step explanation:

18 2/3−3 5/8

=15 1/24

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3 years ago
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